TGPSC MPSO / ASO · Paper II · Topic 8
TGPSC MPSO / ASO Basics of Computers questions with answers
18 questions from TGPSC ASO Paper II Mock 1 with answers and TGPSC ASO Paper II Challenge 1 with answers. Try each one, then tap Show answer.
8.1Number systems & conversionsNotesPractise this chapter · Set 1 free
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What is the octal equivalent of the hexadecimal number (3A7)₁₆?
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Answer D. 1647
Convert through binary: (3A7)₁₆ = 0011 1010 0111. Regroup in threes from the right: 001 110 100 111 → 1 6 4 7. So (3A7)₁₆ = (1647)₈ (both equal 935 in decimal).
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Match List I (number) with List II (decimal value):
List I:
A. (1110)₂
B. (21)₈
C. (1C)₁₆
D. (101011)₂
List II:
1. 17
2. 43
3. 14
4. 28
Select the correct answer using the code given below.
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Answer D. A-3, B-1, C-4, D-2
(1110)₂ = 8 + 4 + 2 = 14; (21)₈ = 16 + 1 = 17; (1C)₁₆ = 16 + 12 = 28; (101011)₂ = 32 + 8 + 2 + 1 = 43.
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Consider the following statements:
1. In a four-digit hexadecimal integer, the place value of the leftmost position is 16³.
2. The hexadecimal letters A to F stand for the decimal values 10 to 15.
3. 8 is a valid digit in the octal system.
4. The binary system uses only two symbols, 0 and 1.
Which of the statements given above are correct?
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Answer C. 1, 2 and 4 only
Place values of a four-digit hex integer are 16³, 16², 16¹, 16⁰, so 1 is correct; A–F = 10–15, so 2 is correct; octal digits are 0–7, so 3 is wrong; binary uses 0 and 1, so 4 is correct.
Source: Standard B.Com/B.Sc. Computer Fundamentals textbook (Telugu Akademi), Number Systems
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Consider the following statements:
1. Each octal digit can be written as a group of exactly three binary digits.
2. Each hexadecimal digit can be written as a group of exactly four binary digits.
Which of the statements given above is/are correct?
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Answer C. Both 1 and 2
Because 8 = 2³, each octal digit 0–7 matches a 3-bit group 000–111; because 16 = 2⁴, each hexadecimal digit 0–F matches a 4-bit group 0000–1111.
Source: Standard B.Com/B.Sc. Computer Fundamentals textbook (Telugu Akademi), Number Systems
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Match List I (number system) with List II (base):
List I:
A. Binary
B. Octal
C. Decimal
D. Hexadecimal
List II:
1. 16
2. 2
3. 10
4. 8
Select the correct answer using the code given below.
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Answer A. A-2, B-4, C-3, D-1
Binary = base 2, octal = base 8, decimal = base 10, hexadecimal = base 16.
Source: Standard B.Com/B.Sc. Computer Fundamentals textbook (Telugu Akademi), Number Systems
8.1Codes, bits, bytes, words & memoryNotesPractise this chapter · Set 1 free
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The Gray code 1101 is converted to binary. What is the result?
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Answer B. 1001
Copy the MSB, then each binary bit = previous binary bit ⊕ current Gray bit: 1, 1⊕1 = 0, 0⊕0 = 0, 0⊕1 = 1, so binary = 1001 (decimal 9). Check: 1001 → Gray 1101.
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Consider the following statements about Unicode:
1. The first 128 Unicode code points are the same as the ASCII characters.
2. UTF-8 always uses exactly 2 bytes for every character.
Which of the statements given above is/are correct?
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Answer A. 1 only
Unicode code points U+0000 to U+007F are identical to ASCII. UTF-8 is a variable-length encoding using 1 to 4 bytes per character (ASCII characters take 1 byte).
Source: The Unicode Standard, Encoding forms
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Consider the following statements:
1. The 4-bit groups 1010 to 1111 are invalid in BCD (8421) code.
2. BCD usually needs more bits than pure binary to represent the same number.
3. Gray code is a weighted code.
Which of the statements given above are correct?
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Answer B. 1 and 2 only
BCD uses only 10 of the 16 four-bit groups (1010–1111 are invalid), so it is less compact than binary (e.g. 99 needs 8 bits in BCD but 7 in binary). Gray code is unweighted.
Source: Standard digital logic texts (M. Morris Mano, Digital Logic and Computer Design), Binary codes
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Consider the following statements:
1. BCD (8421) is a weighted code.
2. Excess-3 is a weighted code.
Which of the statements given above is/are correct?
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Answer A. 1 only
In 8421 BCD each bit position carries a weight (8, 4, 2, 1). Excess-3 is BCD + 3, so its bits do not carry fixed weights; it is an unweighted code, like Gray code.
Source: Standard digital logic texts (M. Morris Mano), Binary codes
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Using the binary convention (1 KB = 1024 bytes), which of the following pairs is NOT correctly matched?
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Answer C. 1 MB : 1024 bytes
1 nibble = 4 bits, 1 byte = 8 bits, 1 KB = 1024 bytes, 1 MB = 1024 KB = 2^20 bytes and 1 GB = 1024 MB. 1024 bytes is 1 KB, not 1 MB.
Source: Standard computer fundamentals texts (P.K. Sinha, Computer Fundamentals), Units of storage
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A memory chip is organised as 32K × 8 bits (32K locations of one byte each). How many address lines does one chip need, and how many such chips are needed to build a 256 KB byte-addressable memory?
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Answer B. 15 address lines; 8 chips
One chip needs 15 address lines, and 8 chips are needed. 32K = 32 × 1,024 = 2¹⁵ locations, so 15 address lines are needed to select one of them. Each chip stores 32 KB, because each location holds 8 bits = 1 byte. So 256 KB ÷ 32 KB = 8 chips.
Source: Standard computer fundamentals (number systems, data representation and logic operations)
8.1Arithmetic & logic operations, algorithms & flowchartsNotesPractise this chapter · Set 1 free
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Using 8-bit 2's complement arithmetic, 00111100 (60) is subtracted from 00101101 (45) by adding the 2's complement of 60. What is the 8-bit result?
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Answer D. 11110001
2's complement of 00111100 is 11000100; 00101101 + 11000100 = 11110001, which is −15.
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Consider the following statements:
1. In a rotate operation no bit is lost; the bit moved out at one end comes back at the other end.
2. Shifting an unsigned number left by one place doubles it, provided no 1 bit is moved out of the leftmost position.
Which of the statements given above is/are correct?
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Answer C. Both 1 and 2
Both are correct: a rotation is circular, and a left shift multiplies by 2 as long as the result still fits in the register.
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Consider the following statements about the XNOR gate:
1. Its output is 1 when both inputs are equal.
2. It is the complement of the XOR gate.
3. For inputs A and B its output is A·B + A'·B'.
Which of the statements given above are correct?
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Answer D. 1, 2 and 3
XNOR (equivalence gate) gives 1 for inputs 00 and 11; it is NOT of XOR, and its expression is A·B + A'·B'.
Source: Standard computer fundamentals textbook (e.g., P. K. Sinha, Computer Fundamentals), Logic Gates
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Which of the following pairs of flowchart symbol and its use is NOT correctly matched?
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Answer C. Small circle : start or stop of the flowchart
Start and Stop use the oval (terminal) symbol; the small circle is a connector.
8.1MS-Office: Word, Excel & PowerPointNotesPractise this chapter · Set 1 free
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Columns in a worksheet are labelled A, B, …, Z, AA, AB, …. What is the column number of column AB?
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Answer B. 28
Column letters act as a base-26 code with A = 1 … Z = 26. AB = 1 × 26 + 2 = 28.
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Match List I (chart type) with List II (best use):
List I:
A. Pie chart
B. Line chart
C. Column chart
D. Scatter (XY) chart
List II:
1. Trend of a value over time
2. Relationship between two numeric variables
3. Share of each part in a whole
4. Comparison of values across categories
Select the correct answer using the code given below.
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Answer B. A-3, B-1, C-4, D-2
Pie shows parts of a whole; line shows change over time; column compares categories; scatter plots paired numeric values to show a relationship.
Source: MS Excel / LibreOffice Calc documentation; Telugu Akademi B.Com Computer Applications, spreadsheets
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In MS-Excel, cell C2 contains the formula =$A2*B$1. This cell is copied and pasted into cell E5. Which formula will E5 contain?
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Answer D. =$A5*D$1
E5 will contain =$A5*D$1. Copying from C2 to E5 moves the formula 2 columns right and 3 rows down. In $A2 the column is fixed but the row is relative, so it becomes $A5. In B$1 the row is fixed but the column is relative, so it becomes D$1.
Source: Standard MS-Office knowledge (Excel cell references)
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