TGPSC MPSO / ASO · Paper I · Topic 16

TGPSC MPSO / ASO Logical Reasoning, Analytical Ability & Data Interpretation questions with answers

20 questions from TGPSC ASO Paper I Mock 1 with answers. Try each one, then tap Show answer.

16.8Series & coding-decodingNotesPractise this chapter · Set 1 free

  1. In a certain code, BAT is written as 69 and ROAD is written as 152. Using the same rule, how is ANDHRA written?

    1. A276
    2. B46
    3. C138
    4. D230
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    Answer A. 276

    BAT: (2 + 1 + 20) x 3 = 69 and ROAD: (18 + 15 + 1 + 4) x 4 = 152, so code = (sum of letter positions) x (number of letters). ANDHRA: (1 + 14 + 4 + 8 + 18 + 1) x 6 = 46 x 6 = 276.

  2. If '+' means 'x', '-' means '+', 'x' means '÷' and '÷' means '-', then what is the value of 16 x 4 + 3 - 8 ÷ 2?

    1. A18
    2. B22
    3. C2
    4. D63
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    Answer A. 18

    16 x 4 + 3 - 8 ÷ 2 becomes 16 ÷ 4 x 3 + 8 - 2. By BODMAS: 4 x 3 = 12, 12 + 8 - 2 = 18.

  3. In a certain code, LOTUS is written as MNUTT. Which word is written as SNTD in the same code?

    1. ARISE
    2. BROPE
    3. CNOSE
    4. DROSE
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    Answer D. ROSE

    LOTUS -> MNUTT uses +1, -1, +1, -1, +1. To decode, reverse the steps: S-1 = R, N+1 = O, T-1 = S, D+1 = E, giving ROSE.

  4. In a certain code, MANGO is written as NBOHP. How is GUAVA written in that code?

    1. AHVBWB
    2. BHVBXB
    3. CHUBWB
    4. DIVBWB
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    Answer A. HVBWB

    MANGO -> NBOHP shows each letter is moved one place forward (+1). So GUAVA -> HVBWB.

  5. If PEN is coded as 16-5-14, how is INK coded?

    1. A9-13-11
    2. B9-14-11
    3. C8-14-11
    4. D9-14-12
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    Answer B. 9-14-11

    P = 16, E = 5, N = 14, so each letter is coded by its position. INK -> 9-14-11.

16.10Relations, directions & arrangementsNotesPractise this chapter · Set 1 free

  1. Read the information and answer the question.

    Six friends J, K, L, M, N and O sit at equal distances around a circular table at a get-together in Machilipatnam. Exactly three of them face the centre and the other three face away from the centre.

    (i) K sits opposite J.

    (ii) J faces the centre, and O sits immediately to the right of J.

    (iii) O and J face opposite directions.

    (iv) N sits immediately to the left of K.

    (v) M sits immediately to the right of N.

    (vi) L faces the centre.

    (vii) M faces the same direction as K.

    Who sits immediately to the left of O?

    1. AJ
    2. BK
    3. CM
    4. DL
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    Answer D. L

    For a person facing the centre, right is the anticlockwise side; for a person facing away, right is the clockwise side. A Python search gives one arrangement; going clockwise from J: J (centre), M (away), N (centre), K (away), L (centre), O (away). O faces away from the centre, so his left is the anticlockwise side, where L sits.

  2. If A @ B means A is the father of B, A # B means A is the daughter of B, A $ B means A is the sister of B and A % B means A is the husband of B, then in the expression L @ M $ N, how is N related to L?

    1. ACannot be determined
    2. BSon
    3. CDaughter
    4. DNephew
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    Answer A. Cannot be determined

    L @ M: L is M's father. M $ N: M is N's sister, so N is also L's child. N's gender is not known, so son or daughter cannot be fixed.

  3. In a code, North-East is called West, South-East is called North, and all the other directions are renamed in the same manner. What will South-West be called?

    1. ANorth-West
    2. BSouth
    3. CWest
    4. DEast
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    Answer D. East

    North-East (45°) becomes West (270°), a clockwise rotation of 225°. Check: South-East (135°) + 225° = 360° = North. So South-West (225°) + 225° = 450° = 90°, East.

  4. Showing a boy, Meena remarked, "My mother-in-law's husband has only one son, and this boy is that son's son." What is the boy to Meena?

    1. ANephew
    2. BBrother-in-law
    3. CSon
    4. DGrandson
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    Answer C. Son

    Meena's mother-in-law's husband is her father-in-law. His only son is Meena's husband. The son of Meena's husband is Meena's son.

  5. Ravi is the brother of Sita. Sita is the daughter of Gopal, who is a man. How is Gopal related to Ravi?

    1. APaternal uncle
    2. BGrandfather
    3. CBrother
    4. DFather
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    Answer D. Father

    Brother and sister have the same parents. Gopal (a man) is Sita's parent, so he is Ravi's father.

16.8Syllogism & verbal reasoningNotesPractise this chapter · Set 1 free

  1. Statements:

    1. Some cities are towns.

    2. All towns are villages.

    Conclusions:

    I. All cities being villages is a possibility.

    II. Some villages are cities.

    Considering the statements to be true even if they appear to be at variance with commonly known facts, which of the conclusions logically follow(s)?

    1. AOnly I follows
    2. BOnly II follows
    3. CBoth I and II follow
    4. DNeither I nor II follows
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    Answer C. Both I and II follow

    Both I and II follow. Some cities are towns and all towns are villages, so some cities are villages (and so some villages are cities). Nothing stops all cities from being villages, so I is a valid possibility.

  2. Statements: A ≥ B > C; C < D ≤ E

    Conclusions:

    I. A > C

    II. E > C

    Which of the conclusions definitely follow(s)?

    1. AOnly I follows
    2. BOnly II follows
    3. CBoth I and II follow
    4. DNeither I nor II follows
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    Answer C. Both I and II follow

    A ≥ B > C, so A > C. C < D ≤ E reads E ≥ D > C, so E > C. Both follow.

16.13Calendar, clock & figuresNotesPractise this chapter · Set 1 free

  1. What is the minimum number of straight cuts needed to cut a cube into 64 identical small cubes, if the pieces are not moved between cuts?

    1. A9
    2. B6
    3. C12
    4. D8
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    Answer A. 9

    64 = 4 x 4 x 4, so each direction must be divided into 4 parts, which needs 3 cuts. Total = 3 + 3 + 3 = 9 cuts.

  2. A leap year begins on a Tuesday. On which day of the week does that year end?

    1. AWednesday
    2. BTuesday
    3. CThursday
    4. DMonday
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    Answer A. Wednesday

    A leap year has 366 days, so 31 December is the 366th day, i.e. 365 days after 1 January. 365 leaves 1 odd day, so 31 December is Tuesday + 1 = Wednesday.

16.1Numerical abilityNotesPractise this chapter · Set 1 free

  1. If Kavya walks to her office at 5 km/h she is 6 minutes late, but at 6 km/h she is 4 minutes early. How far is the office?

    1. A4 km
    2. B6 km
    3. C5 km
    4. D3 km
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    Answer C. 5 km

    Time difference = 6 + 4 = 10 minutes = 1/6 hour. d/5 - d/6 = d/30 = 1/6, so d = 5 km.

  2. How many times does the digit 7 appear when all the integers from 1 to 100 are written down?

    1. A19
    2. B10
    3. C20
    4. D11
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    Answer C. 20

    Units place: 7, 17, ..., 97 (10 times). Tens place: 70 to 79 (10 times). Total 20 (77 contributes 2).

16.6Data interpretation & sufficiencyNotesPractise this chapter · Set 1 free

  1. Sales of a cooperative society were Rs 50 lakh in 2023 and Rs 64 lakh in 2024 (hypothetical data). Two pie charts give the share of each item:

    2023: Rice 40%, Pulses 25%, Oil 20%, Others 15%

    2024: Rice 35%, Pulses 30%, Oil 20%, Others 15%

    By how much did the sales of pulses increase from 2023 to 2024?

    1. ARs 3.2 lakh
    2. BRs 2.5 lakh
    3. CRs 6.7 lakh
    4. DRs 14 lakh
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    Answer C. Rs 6.7 lakh

    Pulses 2023 = 25% of 50 = 12.5 lakh; 2024 = 30% of 64 = 19.2 lakh. Increase = 19.2 − 12.5 = Rs 6.7 lakh.

    Source: Hypothetical data

  2. The monthly budget of a hostel is Rs 2,40,000 (hypothetical data). A pie chart shows its spending as follows: Food 40%, Salaries 25%, Electricity 12%, Maintenance 8%, Others 15%.

    By how much does the spending on Food exceed the spending on Electricity?

    1. ARs 67,200
    2. BRs 96,000
    3. CRs 28,800
    4. DRs 1,24,800
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    Answer A. Rs 67,200

    Difference in share = 40% − 12% = 28%. Amount = 28/100 × 2,40,000 = Rs 67,200 (Food 96,000 − Electricity 28,800).

    Source: Hypothetical data

16.6Summary statistics: mean, median, mode, varianceNotesPractise this chapter · Set 1 free

  1. Find the mean of the following distribution.

    Class: 0–20 20–40 40–60 60–80 80–100

    Frequency: 5 8 12 10 5

    1. A41
    2. B50
    3. C51
    4. D61
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    Answer C. 51

    Σfx = 5×10 + 8×30 + 12×50 + 10×70 + 5×90 = 2040; Σf = 40; mean = 51.

  2. A 'less than' cumulative frequency table is given.

    Marks less than: 10 20 30 40 50

    Number of students: 4 12 25 34 40

    In which class does the median lie?

    1. A10–20
    2. B20–30
    3. C30–40
    4. D40–50
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    Answer B. 20–30

    N = 40, N/2 = 20. The cumulative frequency is 12 below 20 marks and 25 below 30 marks, so the 20th student lies in 20–30.

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